Base | Representation |
---|---|
bin | 11000100001001010001… |
… | …100101010100100100101 |
3 | 12222001221121221111220112 |
4 | 120201022030222210211 |
5 | 210101104213422432 |
6 | 3330004114342405 |
7 | 232504461551315 |
oct | 30411214524445 |
9 | 5861847844815 |
10 | 1684872014117 |
11 | 59a606366916 |
12 | 23265828aa05 |
13 | c2b62527936 |
14 | 5b79652d445 |
15 | 2dc626777b2 |
hex | 1884a32a925 |
1684872014117 has 2 divisors, whose sum is σ = 1684872014118. Its totient is φ = 1684872014116.
The previous prime is 1684872014081. The next prime is 1684872014207. The reversal of 1684872014117 is 7114102784861.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1564578190561 + 120293823556 = 1250831^2 + 346834^2 .
It is a cyclic number.
It is not a de Polignac number, because 1684872014117 - 28 = 1684872013861 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1684872010117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 842436007058 + 842436007059.
It is an arithmetic number, because the mean of its divisors is an integer number (842436007059).
Almost surely, 21684872014117 is an apocalyptic number.
It is an amenable number.
1684872014117 is a deficient number, since it is larger than the sum of its proper divisors (1).
1684872014117 is an equidigital number, since it uses as much as digits as its factorization.
1684872014117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 602112, while the sum is 50.
Adding to 1684872014117 its reverse (7114102784861), we get a palindrome (8798974798978).
The spelling of 1684872014117 in words is "one trillion, six hundred eighty-four billion, eight hundred seventy-two million, fourteen thousand, one hundred seventeen".
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