Base | Representation |
---|---|
bin | 1001110101010001010… |
… | …0010110000110110101 |
3 | 121011000012122222012022 |
4 | 2131110110112012311 |
5 | 10231421044002432 |
6 | 205333334202525 |
7 | 15126645143315 |
oct | 2352424260665 |
9 | 534005588168 |
10 | 168918344117 |
11 | 65702002096 |
12 | 288a24b3445 |
13 | 12c0cb29c13 |
14 | 8266151445 |
15 | 45d98d9b12 |
hex | 27545161b5 |
168918344117 has 2 divisors, whose sum is σ = 168918344118. Its totient is φ = 168918344116.
The previous prime is 168918344107. The next prime is 168918344167. The reversal of 168918344117 is 711443819861.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 167281818001 + 1636526116 = 409001^2 + 40454^2 .
It is a cyclic number.
It is not a de Polignac number, because 168918344117 - 28 = 168918343861 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (168918344107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 84459172058 + 84459172059.
It is an arithmetic number, because the mean of its divisors is an integer number (84459172059).
Almost surely, 2168918344117 is an apocalyptic number.
It is an amenable number.
168918344117 is a deficient number, since it is larger than the sum of its proper divisors (1).
168918344117 is an equidigital number, since it uses as much as digits as its factorization.
168918344117 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1161216, while the sum is 53.
The spelling of 168918344117 in words is "one hundred sixty-eight billion, nine hundred eighteen million, three hundred forty-four thousand, one hundred seventeen".
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