Base | Representation |
---|---|
bin | 11000100110010011010… |
… | …111000011101000010111 |
3 | 12222121012111100221011022 |
4 | 120212103113003220113 |
5 | 210143411434123023 |
6 | 3332320111231355 |
7 | 233061356454032 |
oct | 30462327035027 |
9 | 5877174327138 |
10 | 1690394442263 |
11 | 5a198a65991a |
12 | 23373981855b |
13 | c3532691cb7 |
14 | 5bb5bb44019 |
15 | 2de873c77c8 |
hex | 189935c3a17 |
1690394442263 has 2 divisors, whose sum is σ = 1690394442264. Its totient is φ = 1690394442262.
The previous prime is 1690394442151. The next prime is 1690394442301. The reversal of 1690394442263 is 3622444930961.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1690394442263 - 28 = 1690394442007 is a prime.
It is a super-2 number, since 2×16903944422632 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1690394448263) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 845197221131 + 845197221132.
It is an arithmetic number, because the mean of its divisors is an integer number (845197221132).
Almost surely, 21690394442263 is an apocalyptic number.
1690394442263 is a deficient number, since it is larger than the sum of its proper divisors (1).
1690394442263 is an equidigital number, since it uses as much as digits as its factorization.
1690394442263 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6718464, while the sum is 53.
The spelling of 1690394442263 in words is "one trillion, six hundred ninety billion, three hundred ninety-four million, four hundred forty-two thousand, two hundred sixty-three".
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