Base | Representation |
---|---|
bin | 1001110110000100001… |
… | …0011001000001101101 |
3 | 121011120002012200002102 |
4 | 2131201002121001231 |
5 | 10232340211210133 |
6 | 205410440104445 |
7 | 15135146036444 |
oct | 2354102310155 |
9 | 534502180072 |
10 | 169131741293 |
11 | 65801505599 |
12 | 28941a65125 |
13 | 12c450c5138 |
14 | 828661dd5b |
15 | 45ed4dd7e8 |
hex | 276109906d |
169131741293 has 2 divisors, whose sum is σ = 169131741294. Its totient is φ = 169131741292.
The previous prime is 169131741187. The next prime is 169131741349. The reversal of 169131741293 is 392147131961.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 156608564644 + 12523176649 = 395738^2 + 111907^2 .
It is a cyclic number.
It is not a de Polignac number, because 169131741293 - 222 = 169127546989 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (169131746293) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 84565870646 + 84565870647.
It is an arithmetic number, because the mean of its divisors is an integer number (84565870647).
Almost surely, 2169131741293 is an apocalyptic number.
It is an amenable number.
169131741293 is a deficient number, since it is larger than the sum of its proper divisors (1).
169131741293 is an equidigital number, since it uses as much as digits as its factorization.
169131741293 is an evil number, because the sum of its binary digits is even.
The product of its digits is 244944, while the sum is 47.
The spelling of 169131741293 in words is "one hundred sixty-nine billion, one hundred thirty-one million, seven hundred forty-one thousand, two hundred ninety-three".
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