Base | Representation |
---|---|
bin | 10100001010011… |
… | …10000000011101 |
3 | 102210021012210211 |
4 | 22011032000131 |
5 | 321244442003 |
6 | 24441132421 |
7 | 4122445162 |
oct | 1205160035 |
9 | 383235724 |
10 | 169140253 |
11 | 87525637 |
12 | 4878a111 |
13 | 29070bb9 |
14 | 1866c069 |
15 | ecb096d |
hex | a14e01d |
169140253 has 2 divisors, whose sum is σ = 169140254. Its totient is φ = 169140252.
The previous prime is 169140239. The next prime is 169140281. The reversal of 169140253 is 352041961.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 150847524 + 18292729 = 12282^2 + 4277^2 .
It is an emirp because it is prime and its reverse (352041961) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 169140253 - 25 = 169140221 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (169140203) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 84570126 + 84570127.
It is an arithmetic number, because the mean of its divisors is an integer number (84570127).
Almost surely, 2169140253 is an apocalyptic number.
It is an amenable number.
169140253 is a deficient number, since it is larger than the sum of its proper divisors (1).
169140253 is an equidigital number, since it uses as much as digits as its factorization.
169140253 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6480, while the sum is 31.
The square root of 169140253 is about 13005.3932274268. The cubic root of 169140253 is about 553.0303833095.
The spelling of 169140253 in words is "one hundred sixty-nine million, one hundred forty thousand, two hundred fifty-three".
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