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169411954093 is a prime number
BaseRepresentation
bin1001110111000110111…
…1010100010110101101
3121012021121110221210021
42131301233110112231
510233423430012333
6205454330042141
715145120564414
oct2356157242655
9535247427707
10169411954093
11659356a4618
12289bb879351
1312c8b185625
1482b192247b
154617dde82d
hex2771bd45ad

169411954093 has 2 divisors, whose sum is σ = 169411954094. Its totient is φ = 169411954092.

The previous prime is 169411954091. The next prime is 169411954163. The reversal of 169411954093 is 390459114961.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 109522607364 + 59889346729 = 330942^2 + 244723^2 .

It is a cyclic number.

It is not a de Polignac number, because 169411954093 - 21 = 169411954091 is a prime.

Together with 169411954091, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 169411954093.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (169411954091) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 84705977046 + 84705977047.

It is an arithmetic number, because the mean of its divisors is an integer number (84705977047).

Almost surely, 2169411954093 is an apocalyptic number.

It is an amenable number.

169411954093 is a deficient number, since it is larger than the sum of its proper divisors (1).

169411954093 is an equidigital number, since it uses as much as digits as its factorization.

169411954093 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1049760, while the sum is 52.

The spelling of 169411954093 in words is "one hundred sixty-nine billion, four hundred eleven million, nine hundred fifty-four thousand, ninety-three".