Base | Representation |
---|---|
bin | 11111110001000010… |
… | …11010110101011111 |
3 | 1122000112212220022121 |
4 | 33320201122311133 |
5 | 234411412142002 |
6 | 11500143123411 |
7 | 1142424053104 |
oct | 177041326537 |
9 | 48015786277 |
10 | 17054412127 |
11 | 7261853285 |
12 | 337b5a3567 |
13 | 17ba364b2c |
14 | b7b004aab |
15 | 69c374237 |
hex | 3f885ad5f |
17054412127 has 2 divisors, whose sum is σ = 17054412128. Its totient is φ = 17054412126.
The previous prime is 17054412083. The next prime is 17054412139. The reversal of 17054412127 is 72121445071.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 17054412127 - 215 = 17054379359 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 17054412092 and 17054412101.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (17054412157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8527206063 + 8527206064.
It is an arithmetic number, because the mean of its divisors is an integer number (8527206064).
Almost surely, 217054412127 is an apocalyptic number.
17054412127 is a deficient number, since it is larger than the sum of its proper divisors (1).
17054412127 is an equidigital number, since it uses as much as digits as its factorization.
17054412127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15680, while the sum is 34.
Adding to 17054412127 its reverse (72121445071), we get a palindrome (89175857198).
The spelling of 17054412127 in words is "seventeen billion, fifty-four million, four hundred twelve thousand, one hundred twenty-seven".
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