Base | Representation |
---|---|
bin | 11111110010001101… |
… | …00000010111111101 |
3 | 1122001020011211102012 |
4 | 33321012200113331 |
5 | 234421404243031 |
6 | 11501131341005 |
7 | 1142602514135 |
oct | 177106402775 |
9 | 48036154365 |
10 | 17064134141 |
11 | 72672935aa |
12 | 33828b1765 |
13 | 17bc389cc2 |
14 | b7c415ac5 |
15 | 69d144b2b |
hex | 3f91a05fd |
17064134141 has 2 divisors, whose sum is σ = 17064134142. Its totient is φ = 17064134140.
The previous prime is 17064134117. The next prime is 17064134159. The reversal of 17064134141 is 14143146071.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12030799225 + 5033334916 = 109685^2 + 70946^2 .
It is a cyclic number.
It is not a de Polignac number, because 17064134141 - 26 = 17064134077 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 17064134098 and 17064134107.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (17064134111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8532067070 + 8532067071.
It is an arithmetic number, because the mean of its divisors is an integer number (8532067071).
Almost surely, 217064134141 is an apocalyptic number.
It is an amenable number.
17064134141 is a deficient number, since it is larger than the sum of its proper divisors (1).
17064134141 is an equidigital number, since it uses as much as digits as its factorization.
17064134141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8064, while the sum is 32.
The spelling of 17064134141 in words is "seventeen billion, sixty-four million, one hundred thirty-four thousand, one hundred forty-one".
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