Base | Representation |
---|---|
bin | 11111111000000101… |
… | …00111110011000101 |
3 | 1122011122222012210101 |
4 | 33330002213303011 |
5 | 240022020310441 |
6 | 11510052324101 |
7 | 1144041622204 |
oct | 177402476305 |
9 | 48148865711 |
10 | 17113447621 |
11 | 7292105546 |
12 | 3397313631 |
13 | 17c9664a8a |
14 | b84bb123b |
15 | 6a2636231 |
hex | 3fc0a7cc5 |
17113447621 has 2 divisors, whose sum is σ = 17113447622. Its totient is φ = 17113447620.
The previous prime is 17113447619. The next prime is 17113447639. The reversal of 17113447621 is 12674431171.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12312343521 + 4801104100 = 110961^2 + 69290^2 .
It is a cyclic number.
It is not a de Polignac number, because 17113447621 - 21 = 17113447619 is a prime.
Together with 17113447619, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (17113447651) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8556723810 + 8556723811.
It is an arithmetic number, because the mean of its divisors is an integer number (8556723811).
Almost surely, 217113447621 is an apocalyptic number.
It is an amenable number.
17113447621 is a deficient number, since it is larger than the sum of its proper divisors (1).
17113447621 is an equidigital number, since it uses as much as digits as its factorization.
17113447621 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 28224, while the sum is 37.
Adding to 17113447621 its reverse (12674431171), we get a palindrome (29787878792).
The spelling of 17113447621 in words is "seventeen billion, one hundred thirteen million, four hundred forty-seven thousand, six hundred twenty-one".
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