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1711412641373 is a prime number
BaseRepresentation
bin11000111001111000001…
…001000111111001011101
320001121110021211002000012
4120321320021013321131
5211014433114010443
63350113452213005
7234434254300331
oct30717011077135
96047407732005
101711412641373
115aa895901a06
1223782476a165
13c5501ca95c6
145cb933537c1
152e7b771c118
hex18e78247e5d

1711412641373 has 2 divisors, whose sum is σ = 1711412641374. Its totient is φ = 1711412641372.

The previous prime is 1711412641361. The next prime is 1711412641409. The reversal of 1711412641373 is 3731462141171.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1710332993209 + 1079648164 = 1307797^2 + 32858^2 .

It is a cyclic number.

It is not a de Polignac number, because 1711412641373 - 210 = 1711412640349 is a prime.

It is a super-2 number, since 2×17114126413732 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1711412641373.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1711412641343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 855706320686 + 855706320687.

It is an arithmetic number, because the mean of its divisors is an integer number (855706320687).

Almost surely, 21711412641373 is an apocalyptic number.

It is an amenable number.

1711412641373 is a deficient number, since it is larger than the sum of its proper divisors (1).

1711412641373 is an equidigital number, since it uses as much as digits as its factorization.

1711412641373 is an evil number, because the sum of its binary digits is even.

The product of its digits is 84672, while the sum is 41.

The spelling of 1711412641373 in words is "one trillion, seven hundred eleven billion, four hundred twelve million, six hundred forty-one thousand, three hundred seventy-three".