Base | Representation |
---|---|
bin | 11111111000111111… |
… | …11101110100100000 |
3 | 1122012012110000202022 |
4 | 33330133331310200 |
5 | 240031002440000 |
6 | 11510525241012 |
7 | 1144164201026 |
oct | 177437756440 |
9 | 48165400668 |
10 | 17121140000 |
11 | 7296489988 |
12 | 3399a03168 |
13 | 17cb129193 |
14 | b85c14716 |
15 | 6a3155585 |
hex | 3fc7fdd20 |
17121140000 has 60 divisors (see below), whose sum is σ = 42120621774. Its totient is φ = 6848448000.
The previous prime is 17121139999. The next prime is 17121140017. The reversal of 17121140000 is 4112171.
It can be written as a sum of positive squares in 5 ways, for example, as 313573264 + 16807566736 = 17708^2 + 129644^2 .
It is an unprimeable number.
It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 408029 + ... + 448028.
Almost surely, 217121140000 is an apocalyptic number.
17121140000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
17121140000 is an abundant number, since it is smaller than the sum of its proper divisors (24999481774).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
17121140000 is an frugal number, since it uses more digits than its factorization.
17121140000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 856087 (or 856064 counting only the distinct ones).
The product of its (nonzero) digits is 56, while the sum is 17.
Adding to 17121140000 its reverse (4112171), we get a palindrome (17125252171).
The spelling of 17121140000 in words is "seventeen billion, one hundred twenty-one million, one hundred forty thousand".
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