Base | Representation |
---|---|
bin | 11000111011011000010… |
… | …000101100111000101101 |
3 | 20001202121200012121022021 |
4 | 120323120100230320231 |
5 | 211031233430144441 |
6 | 3350541455550141 |
7 | 234522235204012 |
oct | 30733020547055 |
9 | 6052550177267 |
10 | 1713025240621 |
11 | 6005430a9662 |
12 | 237bb482b351 |
13 | c56cb104046 |
14 | 5cca75a7709 |
15 | 2e85e0a93d1 |
hex | 18ed842ce2d |
1713025240621 has 2 divisors, whose sum is σ = 1713025240622. Its totient is φ = 1713025240620.
The previous prime is 1713025240543. The next prime is 1713025240631. The reversal of 1713025240621 is 1260425203171.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1710118521225 + 2906719396 = 1307715^2 + 53914^2 .
It is a cyclic number.
It is not a de Polignac number, because 1713025240621 - 223 = 1713016852013 is a prime.
It is a super-4 number, since 4×17130252406214 (a number of 50 digits) contains 4444 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1713025240631) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 856512620310 + 856512620311.
It is an arithmetic number, because the mean of its divisors is an integer number (856512620311).
Almost surely, 21713025240621 is an apocalyptic number.
It is an amenable number.
1713025240621 is a deficient number, since it is larger than the sum of its proper divisors (1).
1713025240621 is an equidigital number, since it uses as much as digits as its factorization.
1713025240621 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20160, while the sum is 34.
The spelling of 1713025240621 in words is "one trillion, seven hundred thirteen billion, twenty-five million, two hundred forty thousand, six hundred twenty-one".
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