Base | Representation |
---|---|
bin | 110011000100000… |
… | …1001001111110101 |
3 | 11102102002022002221 |
4 | 1212020021033311 |
5 | 12002113123221 |
6 | 442004202341 |
7 | 60313516345 |
oct | 14610111765 |
9 | 4372068087 |
10 | 1713411061 |
11 | 7aa1a30aa |
12 | 3b99993b1 |
13 | 213c938cb |
14 | 1237b6d25 |
15 | a0652541 |
hex | 662093f5 |
1713411061 has 2 divisors, whose sum is σ = 1713411062. Its totient is φ = 1713411060.
The previous prime is 1713411023. The next prime is 1713411097. The reversal of 1713411061 is 1601143171.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1632968100 + 80442961 = 40410^2 + 8969^2 .
It is an emirp because it is prime and its reverse (1601143171) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1713411061 - 211 = 1713409013 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1713411761) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 856705530 + 856705531.
It is an arithmetic number, because the mean of its divisors is an integer number (856705531).
Almost surely, 21713411061 is an apocalyptic number.
It is an amenable number.
1713411061 is a deficient number, since it is larger than the sum of its proper divisors (1).
1713411061 is an equidigital number, since it uses as much as digits as its factorization.
1713411061 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 504, while the sum is 25.
The square root of 1713411061 is about 41393.3697710153. The cubic root of 1713411061 is about 1196.6133821277.
The spelling of 1713411061 in words is "one billion, seven hundred thirteen million, four hundred eleven thousand, sixty-one".
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