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171365531053 is a prime number
BaseRepresentation
bin1001111110011000101…
…1100111110110101101
3121101022202110221120111
42133212023213312231
510301424033443203
6210420234020021
715244411660153
oct2374613476655
9541282427514
10171365531053
1166748413932
1229265b77611
131320cb27722
1484191753d3
1546ce68226d
hex27e62e7dad

171365531053 has 2 divisors, whose sum is σ = 171365531054. Its totient is φ = 171365531052.

The previous prime is 171365531027. The next prime is 171365531081. The reversal of 171365531053 is 350135563171.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 97695628969 + 73669902084 = 312563^2 + 271422^2 .

It is an emirp because it is prime and its reverse (350135563171) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 171365531053 - 217 = 171365399981 is a prime.

It is a super-2 number, since 2×1713655310532 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 171365530997 and 171365531015.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (171365531083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 85682765526 + 85682765527.

It is an arithmetic number, because the mean of its divisors is an integer number (85682765527).

Almost surely, 2171365531053 is an apocalyptic number.

It is an amenable number.

171365531053 is a deficient number, since it is larger than the sum of its proper divisors (1).

171365531053 is an equidigital number, since it uses as much as digits as its factorization.

171365531053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 141750, while the sum is 40.

The spelling of 171365531053 in words is "one hundred seventy-one billion, three hundred sixty-five million, five hundred thirty-one thousand, fifty-three".