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1714304113 is a prime number
BaseRepresentation
bin110011000101110…
…0011010001110001
311102110202200010221
41212023203101301
512002330212423
6442035253041
760324226114
oct14613432161
94373680127
101714304113
117aa753065
123ba14a181
13214217242
1412396a57b
15a077be5d
hex662e3471

1714304113 has 2 divisors, whose sum is σ = 1714304114. Its totient is φ = 1714304112.

The previous prime is 1714304099. The next prime is 1714304171. The reversal of 1714304113 is 3114034171.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1520064144 + 194239969 = 38988^2 + 13937^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1714304113 is a prime.

It is not a weakly prime, because it can be changed into another prime (1714104113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 857152056 + 857152057.

It is an arithmetic number, because the mean of its divisors is an integer number (857152057).

Almost surely, 21714304113 is an apocalyptic number.

It is an amenable number.

1714304113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1714304113 is an equidigital number, since it uses as much as digits as its factorization.

1714304113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1008, while the sum is 25.

The square root of 1714304113 is about 41404.1557455287. The cubic root of 1714304113 is about 1196.8212428078.

Adding to 1714304113 its reverse (3114034171), we get a palindrome (4828338284).

The spelling of 1714304113 in words is "one billion, seven hundred fourteen million, three hundred four thousand, one hundred thirteen".