Base | Representation |
---|---|
bin | 11000111111000101001… |
… | …100101011010110111101 |
3 | 20002010212201010220121012 |
4 | 120333011030223112331 |
5 | 211112404044322411 |
6 | 3352440141045005 |
7 | 235022604322046 |
oct | 30770514532675 |
9 | 6063781126535 |
10 | 1717000385981 |
11 | 6021a2a57161 |
12 | 238923b56765 |
13 | c5bb283276a |
14 | 5d1634cb8cd |
15 | 2e9e307018b |
hex | 18fc532b5bd |
1717000385981 has 2 divisors, whose sum is σ = 1717000385982. Its totient is φ = 1717000385980.
The previous prime is 1717000385923. The next prime is 1717000385983. The reversal of 1717000385981 is 1895830007171.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1353522828100 + 363477557881 = 1163410^2 + 602891^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1717000385981 is a prime.
It is a super-2 number, since 2×17170003859812 (a number of 25 digits) contains 22 as substring.
Together with 1717000385983, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1717000385983) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 858500192990 + 858500192991.
It is an arithmetic number, because the mean of its divisors is an integer number (858500192991).
Almost surely, 21717000385981 is an apocalyptic number.
It is an amenable number.
1717000385981 is a deficient number, since it is larger than the sum of its proper divisors (1).
1717000385981 is an equidigital number, since it uses as much as digits as its factorization.
1717000385981 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 423360, while the sum is 50.
The spelling of 1717000385981 in words is "one trillion, seven hundred seventeen billion, three hundred eighty-five thousand, nine hundred eighty-one".
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