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172249631 is a prime number
BaseRepresentation
bin10100100010001…
…01001000011111
3110000010012001222
422101011020133
5323043442011
625031523555
74161045341
oct1221051037
9400105058
10172249631
1189259774
12498295bb
13298bc278
1418c3b291
15101c6ddb
hexa44521f

172249631 has 2 divisors, whose sum is σ = 172249632. Its totient is φ = 172249630.

The previous prime is 172249613. The next prime is 172249633. The reversal of 172249631 is 136942271.

Together with previous prime (172249613) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is an emirp because it is prime and its reverse (136942271) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 172249631 - 214 = 172233247 is a prime.

It is a super-2 number, since 2×1722496312 = 59339870759272322, which contains 22 as substring.

Together with 172249633, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 172249591 and 172249600.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (172249633) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 86124815 + 86124816.

It is an arithmetic number, because the mean of its divisors is an integer number (86124816).

Almost surely, 2172249631 is an apocalyptic number.

172249631 is a deficient number, since it is larger than the sum of its proper divisors (1).

172249631 is an equidigital number, since it uses as much as digits as its factorization.

172249631 is an evil number, because the sum of its binary digits is even.

The product of its digits is 18144, while the sum is 35.

The square root of 172249631 is about 13124.3906906187. The cubic root of 172249631 is about 556.3986916219.

The spelling of 172249631 in words is "one hundred seventy-two million, two hundred forty-nine thousand, six hundred thirty-one".