Base | Representation |
---|---|
bin | 100111001011011100010100… |
… | …001010110000110101100111 |
3 | 211121002200120022120020220012 |
4 | 213023130110022300311213 |
5 | 140041112122104022043 |
6 | 1410250103113400435 |
7 | 51202665454033463 |
oct | 4713342412606547 |
9 | 747080508506805 |
10 | 172310131314023 |
11 | 4a9a335301357a |
12 | 173aaa3640911b |
13 | 751ba11188981 |
14 | 3079bd7a114a3 |
15 | 14dc2ae0eca18 |
hex | 9cb7142b0d67 |
172310131314023 has 2 divisors, whose sum is σ = 172310131314024. Its totient is φ = 172310131314022.
The previous prime is 172310131314019. The next prime is 172310131314143. The reversal of 172310131314023 is 320413131013271.
172310131314023 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 172310131314023 - 22 = 172310131314019 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (172310131314323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 86155065657011 + 86155065657012.
It is an arithmetic number, because the mean of its divisors is an integer number (86155065657012).
Almost surely, 2172310131314023 is an apocalyptic number.
172310131314023 is a deficient number, since it is larger than the sum of its proper divisors (1).
172310131314023 is an equidigital number, since it uses as much as digits as its factorization.
172310131314023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9072, while the sum is 32.
Adding to 172310131314023 its reverse (320413131013271), we get a palindrome (492723262327294).
The spelling of 172310131314023 in words is "one hundred seventy-two trillion, three hundred ten billion, one hundred thirty-one million, three hundred fourteen thousand, twenty-three".
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