Base | Representation |
---|---|
bin | 10000000101100111… |
… | …111001001100001101 |
3 | 1122120212110221121121 |
4 | 100011213321030031 |
5 | 240334144310013 |
6 | 11534034200541 |
7 | 1151033250262 |
oct | 200547711415 |
9 | 48525427547 |
10 | 17274213133 |
11 | 7364930001 |
12 | 3421123151 |
13 | 1823a62ab8 |
14 | b9c29d269 |
15 | 6b17e058d |
hex | 4059f930d |
17274213133 has 2 divisors, whose sum is σ = 17274213134. Its totient is φ = 17274213132.
The previous prime is 17274213127. The next prime is 17274213137. The reversal of 17274213133 is 33131247271.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12368331369 + 4905881764 = 111213^2 + 70042^2 .
It is an emirp because it is prime and its reverse (33131247271) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 17274213133 - 25 = 17274213101 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (17274213137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8637106566 + 8637106567.
It is an arithmetic number, because the mean of its divisors is an integer number (8637106567).
Almost surely, 217274213133 is an apocalyptic number.
It is an amenable number.
17274213133 is a deficient number, since it is larger than the sum of its proper divisors (1).
17274213133 is an equidigital number, since it uses as much as digits as its factorization.
17274213133 is an evil number, because the sum of its binary digits is even.
The product of its digits is 21168, while the sum is 34.
The spelling of 17274213133 in words is "seventeen billion, two hundred seventy-four million, two hundred thirteen thousand, one hundred thirty-three".
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