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17423120435213 is a prime number
BaseRepresentation
bin1111110110001010001011…
…1001111000100000001101
32021200122010012221101211202
43331202202321320200031
54240430022312411323
6101020023201555245
73445531111101263
oct375424271704015
967618105841752
1017423120435213
1156081162a1959
121b54873945b25
13994cbb0cb37c
144433d8006433
15203336bd9d28
hexfd8a2e7880d

17423120435213 has 2 divisors, whose sum is σ = 17423120435214. Its totient is φ = 17423120435212.

The previous prime is 17423120435183. The next prime is 17423120435293. The reversal of 17423120435213 is 31253402132471.

17423120435213 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 15094755728809 + 2328364706404 = 3885197^2 + 1525898^2 .

It is a cyclic number.

It is not a de Polignac number, because 17423120435213 - 232 = 17418825467917 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (17423120435293) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8711560217606 + 8711560217607.

It is an arithmetic number, because the mean of its divisors is an integer number (8711560217607).

Almost surely, 217423120435213 is an apocalyptic number.

It is an amenable number.

17423120435213 is a deficient number, since it is larger than the sum of its proper divisors (1).

17423120435213 is an equidigital number, since it uses as much as digits as its factorization.

17423120435213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 120960, while the sum is 38.

Adding to 17423120435213 its reverse (31253402132471), we get a palindrome (48676522567684).

The spelling of 17423120435213 in words is "seventeen trillion, four hundred twenty-three billion, one hundred twenty million, four hundred thirty-five thousand, two hundred thirteen".