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17455545137 is a prime number
BaseRepresentation
bin10000010000011011…
…100111101100110001
31200001111200120100202
4100100123213230301
5241222104421022
612004032524545
71155364454102
oct202033475461
950044616322
1017455545137
117448222468
1234719b0755
1318524b2044
14bb83c23a9
156c26ad592
hex4106e7b31

17455545137 has 2 divisors, whose sum is σ = 17455545138. Its totient is φ = 17455545136.

The previous prime is 17455545067. The next prime is 17455545139. The reversal of 17455545137 is 73154555471.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 17324877376 + 130667761 = 131624^2 + 11431^2 .

It is an emirp because it is prime and its reverse (73154555471) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 17455545137 - 28 = 17455544881 is a prime.

Together with 17455545139, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 17455545091 and 17455545100.

It is not a weakly prime, because it can be changed into another prime (17455545139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8727772568 + 8727772569.

It is an arithmetic number, because the mean of its divisors is an integer number (8727772569).

Almost surely, 217455545137 is an apocalyptic number.

It is an amenable number.

17455545137 is a deficient number, since it is larger than the sum of its proper divisors (1).

17455545137 is an equidigital number, since it uses as much as digits as its factorization.

17455545137 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1470000, while the sum is 47.

The spelling of 17455545137 in words is "seventeen billion, four hundred fifty-five million, five hundred forty-five thousand, one hundred thirty-seven".