Base | Representation |
---|---|
bin | 10000010010000000… |
… | …001101001000111101 |
3 | 1200010100022012010022 |
4 | 100102000031020331 |
5 | 241300332203033 |
6 | 12010414021525 |
7 | 1156134544034 |
oct | 202200151075 |
9 | 50110265108 |
10 | 17481912893 |
11 | 74610a19a5 |
12 | 347a7a78a5 |
13 | 1857ab4973 |
14 | bbbac771b |
15 | 6c4b6b098 |
hex | 41200d23d |
17481912893 has 2 divisors, whose sum is σ = 17481912894. Its totient is φ = 17481912892.
The previous prime is 17481912829. The next prime is 17481912911. The reversal of 17481912893 is 39821918471.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 17476046809 + 5866084 = 132197^2 + 2422^2 .
It is an emirp because it is prime and its reverse (39821918471) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 17481912893 - 26 = 17481912829 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (17481912193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8740956446 + 8740956447.
It is an arithmetic number, because the mean of its divisors is an integer number (8740956447).
Almost surely, 217481912893 is an apocalyptic number.
It is an amenable number.
17481912893 is a deficient number, since it is larger than the sum of its proper divisors (1).
17481912893 is an equidigital number, since it uses as much as digits as its factorization.
17481912893 is an evil number, because the sum of its binary digits is even.
The product of its digits is 870912, while the sum is 53.
The spelling of 17481912893 in words is "seventeen billion, four hundred eighty-one million, nine hundred twelve thousand, eight hundred ninety-three".
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