Base | Representation |
---|---|
bin | 11010001100011000000… |
… | …111110101011011001111 |
3 | 20101002002211001011001102 |
4 | 122030120013311123033 |
5 | 213442342434112142 |
6 | 3454523505133315 |
7 | 244021402406033 |
oct | 32143007653317 |
9 | 6332084034042 |
10 | 1799996004047 |
11 | 63441290044a |
12 | 250a2702a23b |
13 | 10097b476437 |
14 | 6319804c1c3 |
15 | 31c4e519532 |
hex | 1a3181f56cf |
1799996004047 has 2 divisors, whose sum is σ = 1799996004048. Its totient is φ = 1799996004046.
The previous prime is 1799996004007. The next prime is 1799996004049. The reversal of 1799996004047 is 7404006999971.
It is a strong prime.
It is an emirp because it is prime and its reverse (7404006999971) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1799996004047 - 26 = 1799996003983 is a prime.
It is a super-2 number, since 2×17999960040472 (a number of 25 digits) contains 22 as substring.
Together with 1799996004049, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1799996004049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 899998002023 + 899998002024.
It is an arithmetic number, because the mean of its divisors is an integer number (899998002024).
Almost surely, 21799996004047 is an apocalyptic number.
1799996004047 is a deficient number, since it is larger than the sum of its proper divisors (1).
1799996004047 is an equidigital number, since it uses as much as digits as its factorization.
1799996004047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 30862944, while the sum is 65.
The spelling of 1799996004047 in words is "one trillion, seven hundred ninety-nine billion, nine hundred ninety-six million, four thousand, forty-seven".
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