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185040461231 is a prime number
BaseRepresentation
bin1010110001010101000…
…1010101110110101111
3122200121210021101011222
42230111101111312233
511012430324224411
6221001215133555
716240321653233
oct2542521256657
9580553241158
10185040461231
117152557531a
122ba418142bb
13145abc9b8a2
148d553d05c3
154c2eea34db
hex2b15455daf

185040461231 has 2 divisors, whose sum is σ = 185040461232. Its totient is φ = 185040461230.

The previous prime is 185040461213. The next prime is 185040461233. The reversal of 185040461231 is 132164040581.

Together with previous prime (185040461213) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 185040461231 - 214 = 185040444847 is a prime.

It is a super-2 number, since 2×1850404612312 (a number of 23 digits) contains 22 as substring.

Together with 185040461233, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 185040461191 and 185040461200.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (185040461233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 92520230615 + 92520230616.

It is an arithmetic number, because the mean of its divisors is an integer number (92520230616).

Almost surely, 2185040461231 is an apocalyptic number.

185040461231 is a deficient number, since it is larger than the sum of its proper divisors (1).

185040461231 is an equidigital number, since it uses as much as digits as its factorization.

185040461231 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 23040, while the sum is 35.

The spelling of 185040461231 in words is "one hundred eighty-five billion, forty million, four hundred sixty-one thousand, two hundred thirty-one".