Base | Representation |
---|---|
bin | 1000100001110101100100… |
… | …00010001110001010111101 |
3 | 2110101221110020120221011022 |
4 | 10100322302002032022331 |
5 | 4424234324410003432 |
6 | 103515502003433525 |
7 | 3643663530610625 |
oct | 420726202161275 |
9 | 73357406527138 |
10 | 18754814141117 |
11 | 5a8096571141a |
12 | 212a9853858a5 |
13 | a60757442332 |
14 | 48ba48923885 |
15 | 227cc8297b12 |
hex | 110eb208e2bd |
18754814141117 has 2 divisors, whose sum is σ = 18754814141118. Its totient is φ = 18754814141116.
The previous prime is 18754814141093. The next prime is 18754814141159. The reversal of 18754814141117 is 71114141845781.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 16430854143001 + 2323959998116 = 4053499^2 + 1524454^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-18754814141117 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (18754814141177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9377407070558 + 9377407070559.
It is an arithmetic number, because the mean of its divisors is an integer number (9377407070559).
Almost surely, 218754814141117 is an apocalyptic number.
It is an amenable number.
18754814141117 is a deficient number, since it is larger than the sum of its proper divisors (1).
18754814141117 is an equidigital number, since it uses as much as digits as its factorization.
18754814141117 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1003520, while the sum is 53.
Adding to 18754814141117 its reverse (71114141845781), we get a palindrome (89868955986898).
The spelling of 18754814141117 in words is "eighteen trillion, seven hundred fifty-four billion, eight hundred fourteen million, one hundred forty-one thousand, one hundred seventeen".
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