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18813941 is a prime number
BaseRepresentation
bin100011111000…
…1001111110101
31022101211212122
41013301033311
514304021231
61511125325
7315626066
oct107611765
938354778
1018813941
11a690213
126373845
133b89613
1426da56d
1519b977b
hex11f13f5

18813941 has 2 divisors, whose sum is σ = 18813942. Its totient is φ = 18813940.

The previous prime is 18813913. The next prime is 18813943. The reversal of 18813941 is 14931881.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 18309841 + 504100 = 4279^2 + 710^2 .

It is an emirp because it is prime and its reverse (14931881) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-18813941 is a prime.

It is a Sophie Germain prime.

Together with 18813943, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (18813943) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9406970 + 9406971.

It is an arithmetic number, because the mean of its divisors is an integer number (9406971).

Almost surely, 218813941 is an apocalyptic number.

It is an amenable number.

18813941 is a deficient number, since it is larger than the sum of its proper divisors (1).

18813941 is an equidigital number, since it uses as much as digits as its factorization.

18813941 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6912, while the sum is 35.

The square root of 18813941 is about 4337.5040057618. The cubic root of 18813941 is about 265.9662883389.

The spelling of 18813941 in words is "eighteen million, eight hundred thirteen thousand, nine hundred forty-one".