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1913405483380 = 225128467744707
BaseRepresentation
bin11011110101111111110…
…110101010100101110100
320202220211111222121210211
4123311333312222211310
5222322123300432010
64023001211555204
7255144654154336
oct33657766524564
96686744877724
101913405483380
1167851a570876
1226a9b775bb04
1310b583137a21
1468875d89456
1534b8aadd08a
hex1bd7fdaa974

1913405483380 has 24 divisors (see below), whose sum is σ = 4018188188448. Its totient is φ = 765355207968.

The previous prime is 1913405483351. The next prime is 1913405483413. The reversal of 1913405483380 is 833845043191.

It is a super-2 number, since 2×19134054833802 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2196987 + ... + 2941693.

It is an arithmetic number, because the mean of its divisors is an integer number (167424507852).

Almost surely, 21913405483380 is an apocalyptic number.

1913405483380 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1913405483380 is an abundant number, since it is smaller than the sum of its proper divisors (2104782705068).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1913405483380 is a wasteful number, since it uses less digits than its factorization.

1913405483380 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 873183 (or 873181 counting only the distinct ones).

The product of its (nonzero) digits is 1244160, while the sum is 49.

The spelling of 1913405483380 in words is "one trillion, nine hundred thirteen billion, four hundred five million, four hundred eighty-three thousand, three hundred eighty".

Divisors: 1 2 4 5 10 20 128467 256934 513868 642335 744707 1284670 1489414 2569340 2978828 3723535 7447070 14894140 95670274169 191340548338 382681096676 478351370845 956702741690 1913405483380