Base | Representation |
---|---|
bin | 11100011101000111010… |
… | …011001011110111101111 |
3 | 20220221020121222202202121 |
4 | 130131013103023313233 |
5 | 224014133010101000 |
6 | 4054145023533411 |
7 | 261162535401250 |
oct | 34350723136757 |
9 | 6827217882677 |
10 | 1955406331375 |
11 | 6943129955a2 |
12 | 276b7975a267 |
13 | 1125178a05c3 |
14 | 6a8dc192b27 |
15 | 35ce80a3b1a |
hex | 1c7474cbdef |
1955406331375 has 32 divisors (see below), whose sum is σ = 2830594590720. Its totient is φ = 1320837328800.
The previous prime is 1955406331339. The next prime is 1955406331393. The reversal of 1955406331375 is 5731336045591.
It is not a de Polignac number, because 1955406331375 - 235 = 1921046593007 is a prime.
It is a super-2 number, since 2×19554063313752 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 16618615 + ... + 16735864.
It is an arithmetic number, because the mean of its divisors is an integer number (88456080960).
Almost surely, 21955406331375 is an apocalyptic number.
1955406331375 is a deficient number, since it is larger than the sum of its proper divisors (875188259345).
1955406331375 is an equidigital number, since it uses as much as digits as its factorization.
1955406331375 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 33354568 (or 33354558 counting only the distinct ones).
The product of its (nonzero) digits is 5103000, while the sum is 52.
The spelling of 1955406331375 in words is "one trillion, nine hundred fifty-five billion, four hundred six million, three hundred thirty-one thousand, three hundred seventy-five".
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