Base | Representation |
---|---|
bin | 1011011010101101100… |
… | …1110101000000011101 |
3 | 200202021222022221001022 |
4 | 2312223121311000131 |
5 | 11203203143443343 |
6 | 230035410053525 |
7 | 20112521500343 |
oct | 2665331650035 |
9 | 622258287038 |
10 | 196149202973 |
11 | 76206125419 |
12 | 32021b7a2a5 |
13 | 1565c5aa959 |
14 | 96ca8c9993 |
15 | 5180372568 |
hex | 2dab67501d |
196149202973 has 2 divisors, whose sum is σ = 196149202974. Its totient is φ = 196149202972.
The previous prime is 196149202969. The next prime is 196149202979. The reversal of 196149202973 is 379202941691.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 135220204729 + 60928998244 = 367723^2 + 246838^2 .
It is a cyclic number.
It is not a de Polignac number, because 196149202973 - 22 = 196149202969 is a prime.
It is a super-3 number, since 3×1961492029733 (a number of 35 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (196149202979) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 98074601486 + 98074601487.
It is an arithmetic number, because the mean of its divisors is an integer number (98074601487).
Almost surely, 2196149202973 is an apocalyptic number.
It is an amenable number.
196149202973 is a deficient number, since it is larger than the sum of its proper divisors (1).
196149202973 is an equidigital number, since it uses as much as digits as its factorization.
196149202973 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1469664, while the sum is 53.
The spelling of 196149202973 in words is "one hundred ninety-six billion, one hundred forty-nine million, two hundred two thousand, nine hundred seventy-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.079 sec. • engine limits •