Base | Representation |
---|---|
bin | 10010010011100101… |
… | …010100110011101101 |
3 | 1212201212001101221201 |
4 | 102103211110303231 |
5 | 310223402420433 |
6 | 13010234125501 |
7 | 1264043301001 |
oct | 222345246355 |
9 | 55655041851 |
10 | 19655904493 |
11 | 8377277a75 |
12 | 3986880891 |
13 | 1b1330b124 |
14 | d46714701 |
15 | 7a094ba7d |
hex | 493954ced |
19655904493 has 2 divisors, whose sum is σ = 19655904494. Its totient is φ = 19655904492.
The previous prime is 19655904469. The next prime is 19655904517. The reversal of 19655904493 is 39440955691.
It is a balanced prime because it is at equal distance from previous prime (19655904469) and next prime (19655904517).
It can be written as a sum of positive squares in only one way, i.e., 18229860324 + 1426044169 = 135018^2 + 37763^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-19655904493 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (19635904493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9827952246 + 9827952247.
It is an arithmetic number, because the mean of its divisors is an integer number (9827952247).
Almost surely, 219655904493 is an apocalyptic number.
It is an amenable number.
19655904493 is a deficient number, since it is larger than the sum of its proper divisors (1).
19655904493 is an equidigital number, since it uses as much as digits as its factorization.
19655904493 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5248800, while the sum is 55.
The spelling of 19655904493 in words is "nineteen billion, six hundred fifty-five million, nine hundred four thousand, four hundred ninety-three".
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