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196881497 is a prime number
BaseRepresentation
bin10111011110000…
…10110001011001
3111201110121122022
423233002301121
5400400201442
631311504225
74610315351
oct1357026131
9451417568
10196881497
11a1152a8a
1255b28075
1331a34a37
141c20db61
15124403d2
hexbbc2c59

196881497 has 2 divisors, whose sum is σ = 196881498. Its totient is φ = 196881496.

The previous prime is 196881491. The next prime is 196881499. The reversal of 196881497 is 794188691.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 168376576 + 28504921 = 12976^2 + 5339^2 .

It is a cyclic number.

It is not a de Polignac number, because 196881497 - 28 = 196881241 is a prime.

It is a super-2 number, since 2×1968814972 = 77524647721922018, which contains 22 as substring.

Together with 196881499, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (196881491) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 98440748 + 98440749.

It is an arithmetic number, because the mean of its divisors is an integer number (98440749).

Almost surely, 2196881497 is an apocalyptic number.

It is an amenable number.

196881497 is a deficient number, since it is larger than the sum of its proper divisors (1).

196881497 is an equidigital number, since it uses as much as digits as its factorization.

196881497 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 870912, while the sum is 53.

The square root of 196881497 is about 14031.4467179974. The cubic root of 196881497 is about 581.7480920740.

The spelling of 196881497 in words is "one hundred ninety-six million, eight hundred eighty-one thousand, four hundred ninety-seven".