19714913800 has 24 divisors (see below), whose sum is σ = 45837175050. Its totient is φ = 7885965440.

The previous prime is 19714913789. The next prime is 19714913819. The reversal of 19714913800 is 831941791.

It can be written as a sum of positive squares in 3 ways, for example, as 13777594884 + 5937318916 = 117378^2 + 77054^2 .

It is a super-2 number, since 2×19714913800² (a number of 21 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 49287085 + ... + 49287484.

Almost surely, 2^19714913800 is an apocalyptic number.

19714913800 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

19714913800 is an abundant number, since it is smaller than the sum of its proper divisors (26122261250).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

19714913800 is a wasteful number, since it uses less digits than its factorization.

19714913800 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 98574585 (or 98574576 counting only the distinct ones).

The product of its (nonzero) digits is 54432, while the sum is 43.

The spelling of 19714913800 in words is "nineteen billion, seven hundred fourteen million, nine hundred thirteen thousand, eight hundred".