Base | Representation |
---|---|
bin | 1000111110111100001110… |
… | …10010010100010001101011 |
3 | 2120221112122200011111120222 |
4 | 10133132013102110101223 |
5 | 10042130340011220412 |
6 | 110003124020240255 |
7 | 4106144651103212 |
oct | 437360722242153 |
9 | 76845580144528 |
10 | 19754824320107 |
11 | 6326a793599a8 |
12 | 227074a84008b |
13 | b03b44863036 |
14 | 4c41d245a079 |
15 | 243d05870072 |
hex | 11f78749446b |
19754824320107 has 2 divisors, whose sum is σ = 19754824320108. Its totient is φ = 19754824320106.
The previous prime is 19754824319999. The next prime is 19754824320137. The reversal of 19754824320107 is 70102342845791.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 19754824320107 - 214 = 19754824303723 is a prime.
It is a super-3 number, since 3×197548243201073 (a number of 41 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (19754824320137) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9877412160053 + 9877412160054.
It is an arithmetic number, because the mean of its divisors is an integer number (9877412160054).
Almost surely, 219754824320107 is an apocalyptic number.
19754824320107 is a deficient number, since it is larger than the sum of its proper divisors (1).
19754824320107 is an equidigital number, since it uses as much as digits as its factorization.
19754824320107 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3386880, while the sum is 53.
The spelling of 19754824320107 in words is "nineteen trillion, seven hundred fifty-four billion, eight hundred twenty-four million, three hundred twenty thousand, one hundred seven".
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