Base | Representation |
---|---|
bin | 111011000100010… |
… | …0111001110011011 |
3 | 12010010102110202122 |
4 | 1312020213032123 |
5 | 13024341004212 |
6 | 524400251455 |
7 | 100054314113 |
oct | 16610471633 |
9 | 5103373678 |
10 | 1981969307 |
11 | 92785196a |
12 | 473910b8b |
13 | 257803406 |
14 | 14b324043 |
15 | b9000272 |
hex | 7622739b |
1981969307 has 2 divisors, whose sum is σ = 1981969308. Its totient is φ = 1981969306.
The previous prime is 1981969289. The next prime is 1981969309. The reversal of 1981969307 is 7039691891.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1981969307 - 222 = 1977775003 is a prime.
Together with 1981969309, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1981969309) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 990984653 + 990984654.
It is an arithmetic number, because the mean of its divisors is an integer number (990984654).
Almost surely, 21981969307 is an apocalyptic number.
1981969307 is a deficient number, since it is larger than the sum of its proper divisors (1).
1981969307 is an equidigital number, since it uses as much as digits as its factorization.
1981969307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 734832, while the sum is 53.
The square root of 1981969307 is about 44519.3138648834. The cubic root of 1981969307 is about 1256.1234062941.
The spelling of 1981969307 in words is "one billion, nine hundred eighty-one million, nine hundred sixty-nine thousand, three hundred seven".
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