1983045601181 has 2 divisors, whose sum is σ = 1983045601182. Its totient is φ = 1983045601180.

The previous prime is 1983045601151. The next prime is 1983045601217. The reversal of 1983045601181 is 1811065403891.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1270431053956 + 712614547225 = 1127134^2 + 844165^2 .

It is an emirp because it is prime and its reverse (1811065403891) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1983045601181 - 2²⁶ = 1982978492317 is a prime.

It is a super-2 number, since 2×1983045601181² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1983045601151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 991522800590 + 991522800591.

It is an arithmetic number, because the mean of its divisors is an integer number (991522800591).

Almost surely, 2^{1983045601181} is an apocalyptic number.

It is an amenable number.

1983045601181 is a deficient number, since it is larger than the sum of its proper divisors (1).

1983045601181 is an equidigital number, since it uses as much as digits as its factorization.

1983045601181 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 207360, while the sum is 47.

The spelling of 1983045601181 in words is "one trillion, nine hundred eighty-three billion, forty-five million, six hundred one thousand, one hundred eighty-one".