Base | Representation |
---|---|
bin | 10010100000000010… |
… | …001110000010011101 |
3 | 1220021102010200022021 |
4 | 102200002032002131 |
5 | 311140342234113 |
6 | 13043055420141 |
7 | 1302161026636 |
oct | 224002160235 |
9 | 56242120267 |
10 | 19864805533 |
11 | 847418a461 |
12 | 3a24824651 |
13 | 1b47690a01 |
14 | d6637288d |
15 | 7b3e6348d |
hex | 4a008e09d |
19864805533 has 2 divisors, whose sum is σ = 19864805534. Its totient is φ = 19864805532.
The previous prime is 19864805509. The next prime is 19864805557. The reversal of 19864805533 is 33550846891.
It is a balanced prime because it is at equal distance from previous prime (19864805509) and next prime (19864805557).
It can be written as a sum of positive squares in only one way, i.e., 16848818809 + 3015986724 = 129803^2 + 54918^2 .
It is a cyclic number.
It is not a de Polignac number, because 19864805533 - 233 = 11274870941 is a prime.
It is a super-2 number, since 2×198648055332 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (19864805563) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9932402766 + 9932402767.
It is an arithmetic number, because the mean of its divisors is an integer number (9932402767).
Almost surely, 219864805533 is an apocalyptic number.
It is an amenable number.
19864805533 is a deficient number, since it is larger than the sum of its proper divisors (1).
19864805533 is an equidigital number, since it uses as much as digits as its factorization.
19864805533 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3110400, while the sum is 52.
The spelling of 19864805533 in words is "nineteen billion, eight hundred sixty-four million, eight hundred five thousand, five hundred thirty-three".
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