Base | Representation |
---|---|
bin | 1011100111010000001… |
… | …0111001101100010011 |
3 | 201001222120110010110122 |
4 | 2321310002321230103 |
5 | 11232101421211032 |
6 | 231353415420455 |
7 | 20262115013462 |
oct | 2716402715423 |
9 | 631876403418 |
10 | 199515413267 |
11 | 77683281aa5 |
12 | 3280138472b |
13 | 15a77b02871 |
14 | 99299bc9d9 |
15 | 52cab53012 |
hex | 2e740b9b13 |
199515413267 has 2 divisors, whose sum is σ = 199515413268. Its totient is φ = 199515413266.
The previous prime is 199515413183. The next prime is 199515413297. The reversal of 199515413267 is 762314515991.
It is a happy number.
199515413267 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 199515413267 - 28 = 199515413011 is a prime.
It is a super-2 number, since 2×1995154132672 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (199515413297) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 99757706633 + 99757706634.
It is an arithmetic number, because the mean of its divisors is an integer number (99757706634).
Almost surely, 2199515413267 is an apocalyptic number.
199515413267 is a deficient number, since it is larger than the sum of its proper divisors (1).
199515413267 is an equidigital number, since it uses as much as digits as its factorization.
199515413267 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2041200, while the sum is 53.
The spelling of 199515413267 in words is "one hundred ninety-nine billion, five hundred fifteen million, four hundred thirteen thousand, two hundred sixty-seven".
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