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19975367053 is a prime number
BaseRepresentation
bin10010100110100111…
…111110100110001101
31220120010011210012101
4102212213332212031
5311402143221203
613102045235101
71305002550505
oct224647764615
956503153171
1019975367053
118520634a14
123a55862a91
131b64561825
14d76d12a05
157bda0241d
hex4a69fe98d

19975367053 has 2 divisors, whose sum is σ = 19975367054. Its totient is φ = 19975367052.

The previous prime is 19975367039. The next prime is 19975367057. The reversal of 19975367053 is 35076357991.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 18387902404 + 1587464649 = 135602^2 + 39843^2 .

It is an emirp because it is prime and its reverse (35076357991) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 19975367053 - 213 = 19975358861 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 19975366985 and 19975367003.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (19975367057) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9987683526 + 9987683527.

It is an arithmetic number, because the mean of its divisors is an integer number (9987683527).

Almost surely, 219975367053 is an apocalyptic number.

It is an amenable number.

19975367053 is a deficient number, since it is larger than the sum of its proper divisors (1).

19975367053 is an equidigital number, since it uses as much as digits as its factorization.

19975367053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5358150, while the sum is 55.

The spelling of 19975367053 in words is "nineteen billion, nine hundred seventy-five million, three hundred sixty-seven thousand, fifty-three".