19983942242909 has 2 divisors, whose sum is σ = 19983942242910. Its totient is φ = 19983942242908.

The previous prime is 19983942242837. The next prime is 19983942242911. The reversal of 19983942242909 is 90924224938991.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 19753491360100 + 230450882809 = 4444490^2 + 480053^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-19983942242909 is a prime.

Together with 19983942242911, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (19983942242939) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9991971121454 + 9991971121455.

It is an arithmetic number, because the mean of its divisors is an integer number (9991971121455).

Almost surely, 2^{19983942242909} is an apocalyptic number.

It is an amenable number.

19983942242909 is a deficient number, since it is larger than the sum of its proper divisors (1).

19983942242909 is an equidigital number, since it uses as much as digits as its factorization.

19983942242909 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 181398528, while the sum is 71.

The spelling of 19983942242909 in words is "nineteen trillion, nine hundred eighty-three billion, nine hundred forty-two million, two hundred forty-two thousand, nine hundred nine".