Base | Representation |
---|---|
bin | 1001000101110010010101… |
… | …11001010011001111100111 |
3 | 2121210000202212022001021001 |
4 | 10202321022321103033213 |
5 | 10110004042242034344 |
6 | 110303143415134131 |
7 | 4132142454153064 |
oct | 442711271231747 |
9 | 77700685261231 |
10 | 19990034330599 |
11 | 64077a9271123 |
12 | 22aa252074347 |
13 | b2008a756738 |
14 | 4d17468b3c6b |
15 | 249ec0009ed4 |
hex | 122e4ae533e7 |
19990034330599 has 2 divisors, whose sum is σ = 19990034330600. Its totient is φ = 19990034330598.
The previous prime is 19990034330593. The next prime is 19990034330611. The reversal of 19990034330599 is 99503343009991.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 19990034330599 - 27 = 19990034330471 is a prime.
It is a super-2 number, since 2×199900343305992 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 19990034330599.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (19990034330593) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9995017165299 + 9995017165300.
It is an arithmetic number, because the mean of its divisors is an integer number (9995017165300).
Almost surely, 219990034330599 is an apocalyptic number.
19990034330599 is a deficient number, since it is larger than the sum of its proper divisors (1).
19990034330599 is an equidigital number, since it uses as much as digits as its factorization.
19990034330599 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 31886460, while the sum is 64.
The spelling of 19990034330599 in words is "nineteen trillion, nine hundred ninety billion, thirty-four million, three hundred thirty thousand, five hundred ninety-nine".
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