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199984133597 is a prime number
BaseRepresentation
bin1011101000111111111…
…0111011010111011101
3201010012020102120212212
42322033332323113131
511234031414233342
6231512122010205
720306536042163
oct2721776732735
9633166376785
10199984133597
11778a3914576
1232912346965
1315b20c55381
149971d51233
155306d8d182
hex2e8ffbb5dd

199984133597 has 2 divisors, whose sum is σ = 199984133598. Its totient is φ = 199984133596.

The previous prime is 199984133533. The next prime is 199984133599. The reversal of 199984133597 is 795331489991.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 185667053881 + 14317079716 = 430891^2 + 119654^2 .

It is a cyclic number.

It is not a de Polignac number, because 199984133597 - 26 = 199984133533 is a prime.

Together with 199984133599, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (199984133599) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 99992066798 + 99992066799.

It is an arithmetic number, because the mean of its divisors is an integer number (99992066799).

Almost surely, 2199984133597 is an apocalyptic number.

It is an amenable number.

199984133597 is a deficient number, since it is larger than the sum of its proper divisors (1).

199984133597 is an equidigital number, since it uses as much as digits as its factorization.

199984133597 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 66134880, while the sum is 68.

The spelling of 199984133597 in words is "one hundred ninety-nine billion, nine hundred eighty-four million, one hundred thirty-three thousand, five hundred ninety-seven".