Base | Representation |
---|---|
bin | 10010101000000111… |
… | …100011000101001101 |
3 | 1220121212022121121201 |
4 | 102220013203011031 |
5 | 311430101421143 |
6 | 13104342225501 |
7 | 1305425523616 |
oct | 225007430515 |
9 | 56555277551 |
10 | 20000420173 |
11 | 8533796778 |
12 | 3a62125291 |
13 | 1b697c3c66 |
14 | d7a394c0d |
15 | 7c0d0064d |
hex | 4a81e314d |
20000420173 has 2 divisors, whose sum is σ = 20000420174. Its totient is φ = 20000420172.
The previous prime is 20000420171. The next prime is 20000420213. The reversal of 20000420173 is 37102400002.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13866711049 + 6133709124 = 117757^2 + 78318^2 .
It is a cyclic number.
It is not a de Polignac number, because 20000420173 - 21 = 20000420171 is a prime.
Together with 20000420171, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 20000420173.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20000420171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10000210086 + 10000210087.
It is an arithmetic number, because the mean of its divisors is an integer number (10000210087).
Almost surely, 220000420173 is an apocalyptic number.
It is an amenable number.
20000420173 is a deficient number, since it is larger than the sum of its proper divisors (1).
20000420173 is an equidigital number, since it uses as much as digits as its factorization.
20000420173 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 336, while the sum is 19.
Adding to 20000420173 its reverse (37102400002), we get a palindrome (57102820175).
The spelling of 20000420173 in words is "twenty billion, four hundred twenty thousand, one hundred seventy-three".
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