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2000100222011 is a prime number
BaseRepresentation
bin11101000110101111010…
…000110110010000111011
321002012121102102122201102
4131012233100312100323
5230232201124101021
64130500001042015
7264334230243353
oct35065720662073
97065542378642
102000100222011
117012684840a1
1228377162630b
131167bb254c38
146cb3bcdbb63
1537061bc800b
hex1d1af43643b

2000100222011 has 2 divisors, whose sum is σ = 2000100222012. Its totient is φ = 2000100222010.

The previous prime is 2000100221939. The next prime is 2000100222013. The reversal of 2000100222011 is 1102220010002.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2000100222011 - 238 = 1725222315067 is a prime.

Together with 2000100222013, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 2000100221983 and 2000100222001.

It is not a weakly prime, because it can be changed into another prime (2000100222013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000050111005 + 1000050111006.

It is an arithmetic number, because the mean of its divisors is an integer number (1000050111006).

Almost surely, 22000100222011 is an apocalyptic number.

2000100222011 is a deficient number, since it is larger than the sum of its proper divisors (1).

2000100222011 is an equidigital number, since it uses as much as digits as its factorization.

2000100222011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16, while the sum is 11.

Adding to 2000100222011 its reverse (1102220010002), we get a palindrome (3102320232013).

The spelling of 2000100222011 in words is "two trillion, one hundred million, two hundred twenty-two thousand, eleven".