Base | Representation |
---|---|
bin | 101101011110100011000100… |
… | …011101111001010010110101 |
3 | 222020011220012201001211210201 |
4 | 231132203010131321102311 |
5 | 202203441202300230232 |
6 | 1545215534335320501 |
7 | 60062225202112105 |
oct | 5536430435712265 |
9 | 866156181054721 |
10 | 200011333211317 |
11 | 5880336a3497a1 |
12 | 1a523652980131 |
13 | 877acac241b94 |
14 | 3756858c71205 |
15 | 181cb48eecbe7 |
hex | b5e8c47794b5 |
200011333211317 has 2 divisors, whose sum is σ = 200011333211318. Its totient is φ = 200011333211316.
The previous prime is 200011333211311. The next prime is 200011333211407. The reversal of 200011333211317 is 713112333110002.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 192720085757956 + 7291247453361 = 13882366^2 + 2700231^2 .
It is a cyclic number.
It is not a de Polignac number, because 200011333211317 - 219 = 200011332687029 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200011333211311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100005666605658 + 100005666605659.
It is an arithmetic number, because the mean of its divisors is an integer number (100005666605659).
Almost surely, 2200011333211317 is an apocalyptic number.
It is an amenable number.
200011333211317 is a deficient number, since it is larger than the sum of its proper divisors (1).
200011333211317 is an equidigital number, since it uses as much as digits as its factorization.
200011333211317 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2268, while the sum is 28.
Adding to 200011333211317 its reverse (713112333110002), we get a palindrome (913123666321319).
The spelling of 200011333211317 in words is "two hundred trillion, eleven billion, three hundred thirty-three million, two hundred eleven thousand, three hundred seventeen".
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