Base | Representation |
---|---|
bin | 101101011110100011000100… |
… | …011101111001010100001111 |
3 | 222020011220012201001211221001 |
4 | 231132203010131321110033 |
5 | 202203441202300231112 |
6 | 1545215534335321131 |
7 | 60062225202112264 |
oct | 5536430435712417 |
9 | 866156181054831 |
10 | 200011333211407 |
11 | 5880336a349873 |
12 | 1a5236529801a7 |
13 | 877acac241c33 |
14 | 3756858c7126b |
15 | 181cb48eecc57 |
hex | b5e8c477950f |
200011333211407 has 2 divisors, whose sum is σ = 200011333211408. Its totient is φ = 200011333211406.
The previous prime is 200011333211317. The next prime is 200011333211411. The reversal of 200011333211407 is 704112333110002.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-200011333211407 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200011333211477) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100005666605703 + 100005666605704.
It is an arithmetic number, because the mean of its divisors is an integer number (100005666605704).
Almost surely, 2200011333211407 is an apocalyptic number.
200011333211407 is a deficient number, since it is larger than the sum of its proper divisors (1).
200011333211407 is an equidigital number, since it uses as much as digits as its factorization.
200011333211407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3024, while the sum is 28.
Adding to 200011333211407 its reverse (704112333110002), we get a palindrome (904123666321409).
The spelling of 200011333211407 in words is "two hundred trillion, eleven billion, three hundred thirty-three million, two hundred eleven thousand, four hundred seven".
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