Base | Representation |
---|---|
bin | 11101000110110000100… |
… | …100010110101111100001 |
3 | 21002012122221121211111112 |
4 | 131012300210112233201 |
5 | 230232222230103433 |
6 | 4130502102153105 |
7 | 264334614306434 |
oct | 35066044265741 |
9 | 7065587554445 |
10 | 2000122112993 |
11 | 701279876114 |
12 | 283778a22795 |
13 | 1167c294ac94 |
14 | 6cb40b9981b |
15 | 37063a9e348 |
hex | 1d1b0916be1 |
2000122112993 has 2 divisors, whose sum is σ = 2000122112994. Its totient is φ = 2000122112992.
The previous prime is 2000122112983. The next prime is 2000122113013. The reversal of 2000122112993 is 3992112210002.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1480327255969 + 519794857024 = 1216687^2 + 720968^2 .
It is a cyclic number.
It is not a de Polignac number, because 2000122112993 - 218 = 2000121850849 is a prime.
It is not a weakly prime, because it can be changed into another prime (2000122112983) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000061056496 + 1000061056497.
It is an arithmetic number, because the mean of its divisors is an integer number (1000061056497).
Almost surely, 22000122112993 is an apocalyptic number.
It is an amenable number.
2000122112993 is a deficient number, since it is larger than the sum of its proper divisors (1).
2000122112993 is an equidigital number, since it uses as much as digits as its factorization.
2000122112993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3888, while the sum is 32.
Adding to 2000122112993 its reverse (3992112210002), we get a palindrome (5992234322995).
The spelling of 2000122112993 in words is "two trillion, one hundred twenty-two million, one hundred twelve thousand, nine hundred ninety-three".
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