Base | Representation |
---|---|
bin | 1011101001000110101… |
… | …0000100011011010001 |
3 | 201010021012021112100012 |
4 | 2322101222010123101 |
5 | 11234111112020423 |
6 | 231515004004305 |
7 | 20310326551106 |
oct | 2722152043321 |
9 | 633235245305 |
10 | 200012220113 |
11 | 77908758372 |
12 | 3291b830695 |
13 | 15b26a0a404 |
14 | 9975982aad |
15 | 530958a078 |
hex | 2e91a846d1 |
200012220113 has 2 divisors, whose sum is σ = 200012220114. Its totient is φ = 200012220112.
The previous prime is 200012220101. The next prime is 200012220143. The reversal of 200012220113 is 311022210002.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 130691649169 + 69320570944 = 361513^2 + 263288^2 .
It is a cyclic number.
It is not a de Polignac number, because 200012220113 - 212 = 200012216017 is a prime.
It is not a weakly prime, because it can be changed into another prime (200012220143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100006110056 + 100006110057.
It is an arithmetic number, because the mean of its divisors is an integer number (100006110057).
Almost surely, 2200012220113 is an apocalyptic number.
It is an amenable number.
200012220113 is a deficient number, since it is larger than the sum of its proper divisors (1).
200012220113 is an equidigital number, since it uses as much as digits as its factorization.
200012220113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 14.
Adding to 200012220113 its reverse (311022210002), we get a palindrome (511034430115).
The spelling of 200012220113 in words is "two hundred billion, twelve million, two hundred twenty thousand, one hundred thirteen".
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