Base | Representation |
---|---|
bin | 1011101001000110101… |
… | …0000100011011101111 |
3 | 201010021012021112101022 |
4 | 2322101222010123233 |
5 | 11234111112021033 |
6 | 231515004004355 |
7 | 20310326551151 |
oct | 2722152043357 |
9 | 633235245338 |
10 | 200012220143 |
11 | 7790875839a |
12 | 3291b8306bb |
13 | 15b26a0a428 |
14 | 9975982ad1 |
15 | 530958a098 |
hex | 2e91a846ef |
200012220143 has 2 divisors, whose sum is σ = 200012220144. Its totient is φ = 200012220142.
The previous prime is 200012220113. The next prime is 200012220157. The reversal of 200012220143 is 341022210002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 200012220143 - 28 = 200012219887 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200012220113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100006110071 + 100006110072.
It is an arithmetic number, because the mean of its divisors is an integer number (100006110072).
Almost surely, 2200012220143 is an apocalyptic number.
200012220143 is a deficient number, since it is larger than the sum of its proper divisors (1).
200012220143 is an equidigital number, since it uses as much as digits as its factorization.
200012220143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 17.
Adding to 200012220143 its reverse (341022210002), we get a palindrome (541034430145).
The spelling of 200012220143 in words is "two hundred billion, twelve million, two hundred twenty thousand, one hundred forty-three".
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