Base | Representation |
---|---|
bin | 11101000111100101100… |
… | …111000011001111110111 |
3 | 21002021221222010101110212 |
4 | 131013211213003033313 |
5 | 230241033033341043 |
6 | 4131130251540035 |
7 | 264365641315313 |
oct | 35074547031767 |
9 | 7067858111425 |
10 | 2001012012023 |
11 | 701696129462 |
12 | 283986a5a61b |
13 | 116905118b5b |
14 | 6cbc7046b43 |
15 | 370b6c83018 |
hex | 1d1e59c33f7 |
2001012012023 has 2 divisors, whose sum is σ = 2001012012024. Its totient is φ = 2001012012022.
The previous prime is 2001012012017. The next prime is 2001012012059. The reversal of 2001012012023 is 3202102101002.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2001012012023 - 24 = 2001012012007 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2001012011989 and 2001012012007.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2001012011023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000506006011 + 1000506006012.
It is an arithmetic number, because the mean of its divisors is an integer number (1000506006012).
Almost surely, 22001012012023 is an apocalyptic number.
2001012012023 is a deficient number, since it is larger than the sum of its proper divisors (1).
2001012012023 is an equidigital number, since it uses as much as digits as its factorization.
2001012012023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 14.
Adding to 2001012012023 its reverse (3202102101002), we get a palindrome (5203114113025).
The spelling of 2001012012023 in words is "two trillion, one billion, twelve million, twelve thousand, twenty-three".
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