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2001102013 is a prime number
BaseRepresentation
bin111011101000110…
…0110010010111101
312011110102111220101
41313101212102331
513044240231023
6530322321101
7100406041441
oct16721462275
95143374811
102001102013
1193762a619
1247a1b9191
1325b771b41
1414daa4821
15baa2e1ad
hex774664bd

2001102013 has 2 divisors, whose sum is σ = 2001102014. Its totient is φ = 2001102012.

The previous prime is 2001102007. The next prime is 2001102031. The reversal of 2001102013 is 3102011002.

Together with next prime (2001102031) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1198059769 + 803042244 = 34613^2 + 28338^2 .

It is a cyclic number.

It is not a de Polignac number, because 2001102013 - 229 = 1464231101 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2001102053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000551006 + 1000551007.

It is an arithmetic number, because the mean of its divisors is an integer number (1000551007).

Almost surely, 22001102013 is an apocalyptic number.

It is an amenable number.

2001102013 is a deficient number, since it is larger than the sum of its proper divisors (1).

2001102013 is an equidigital number, since it uses as much as digits as its factorization.

2001102013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 10.

The square root of 2001102013 is about 44733.6787331424. The cubic root of 2001102013 is about 1260.1524156347.

Adding to 2001102013 its reverse (3102011002), we get a palindrome (5103113015).

The spelling of 2001102013 in words is "two billion, one million, one hundred two thousand, thirteen".